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Richard Montgomery presents: A proof of the Ryser-Brualdi-Stein conjecture for large even n

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A proof of the Ryser-Brualdi-Stein conjecture for large even n by Richard Montgomery

A Latin square of order n is an n by n grid filled using n symbols so that each symbol appears exactly once in each row and column. A transversal in a Latin square is a collection of cells which share no symbol, row or column. The Ryser-Brualdi-Stein conjecture, with origins from 1967, states that every Latin square of order n contains a transversal with n1 cells, and a transversal with n cells if n is odd. Keevash, Pokrovskiy, Sudakov and Yepremyan recently improved the long-standing best known bounds towards this conjecture by showing that every Latin square of order n has a transversal with nO(logn/loglogn) cells. Here, we show, for sufficiently large n, that every Latin square of order n has a transversal with n1 cells.

We also apply our methods to show that, for sufficiently large n, every Steiner triple system of order n has a matching containing at least (n4)/3 edges. This improves a recent result of Keevash, Pokrovskiy, Sudakov and Yepremyan, who found such matchings with n/3O(logn/loglogn) edges, and proves a conjecture of Brouwer from 1981 for large n.

Richard announced the result some months ago in a conference and yesterday the 71-page paper with the details of the proof was uploaded to the arXiv. Congratulations, Richard!

latin2

From right to left: Sherman Stein, Richard Brualdi, Marshal Hall and Herbert Ryser, and Richard Montgomery

I am thankful to Ryan Alweiss for telling me about the paper.


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